-3n^2-12n+180=0

Solution for -3n^2-12n+180=0 equation:

-3n^2-12n+180=0

a = -3; b = -12; c = +180;
Δ = b2-4ac
Δ = -122-4·(-3)·180
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-48}{2*-3}=\frac{-36}{-6}
=+6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+48}{2*-3}=\frac{60}{-6}
=-10
$